Given the total cost function $TC(Q)=Q^3-2Q^2+8Q$ for a wheat farmer in perfect competition, find the functions for $TFC$, $TVC$, $AVC$, $AFC$, $ATC$, and $MC$.
Since $TC(Q)=Q^3-2Q^2+8Q$ has no constant term, $TFC=0$ and $TVC=Q^3-2Q^2+8Q$. Then $AVC=TVC/Q=Q^2-2Q+8$, $AFC=TFC/Q=0$, and $ATC=TC/Q=Q^2-2Q+8$. Marginal cost is $MC=dTC/dQ=3Q^2-4Q+8$.
What you are being asked to extract from $TC(Q)$
A total cost function can be split into a fixed part (cost that does not change with output) and a variable part (cost that changes with output): $$TC(Q)=TFC+TVC(Q).$$ Then the average costs are found by dividing by $Q$, and marginal cost is the derivative of $TC$ with respect to $Q$.
Separating fixed and variable costs
Given: $$TC(Q)=Q^3-2Q^2+8Q.$$ The fixed cost is the part of $TC$ that does not depend on $Q$, meaning the constant term.
- There is no constant term here, so: $$TFC=0.$$
- Therefore: $$TVC(Q)=TC(Q)-TFC=Q^3-2Q^2+8Q.$$
Computing average costs: $AVC$, $AFC$, and $ATC$
Average variable cost: $$AVC(Q)=\frac{TVC(Q)}{Q}=\frac{Q^3-2Q^2+8Q}{Q}=Q^2-2Q+8.$$ Average fixed cost: $$AFC(Q)=\frac{TFC}{Q}=\frac{0}{Q}=0.$$ Average total cost: $$ATC(Q)=\frac{TC(Q)}{Q}=\frac{Q^3-2Q^2+8Q}{Q}=Q^2-2Q+8.$$ Here $ATC=AVC$ because $AFC=0$.
Finding marginal cost $MC$
Marginal cost is the slope of the total cost curve: $$MC(Q)=\frac{dTC}{dQ}.$$ Differentiate term by term: $$\frac{d}{dQ}(Q^3-2Q^2+8Q)=3Q^2-4Q+8.$$ So: $$MC(Q)=3Q^2-4Q+8.$$
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