Draw a parallel circuit diagram with proper symbols containing 1 battery, 3 lights (lamps), and a switch that turns off 2 of the lights (but not the third).
Put the 3 lamps on parallel branches across the battery, and place the switch in series with only the two lamp branches you want to control. That way, opening the switch breaks current to those 2 lamps while the third lamp stays connected directly across the battery. One correct schematic is shown below with standard symbols (battery, switch, lamps).
What the circuit must do
You need a parallel circuit so each light has its own branch across the battery. The switch must interrupt current in exactly two branches, not the whole circuit.
One correct parallel schematic (battery, switch, 3 lamps)
Symbols used: battery $|\ |$, switch $o/\ o$ (open), lamp $(\times)$.
(Lamp 3)
+---------(ร)----------+
| |
| o/ o |
|---/ ----+--(ร)--+ |
| | Lamp1 | |
| +--(ร)--+ |
| Lamp2 |
| |
+----------| |---------+
| |
Battery
Why this switch turns off exactly 2 lights
- Lamp 3 is on its own branch directly across the battery, so it is unaffected by the switch.
- The switch is in series with the part of the circuit that feeds Lamp 1 and Lamp 2.
- When the switch is open, that entire section is disconnected, so Lamp 1 and Lamp 2 go off while Lamp 3 stays on.
Quick check you can do
Close the switch: all three branches have a complete loop to the battery, so all three lamps can light. Open the switch: only Lamp 3 still has a complete loop.
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