Given the DNA sequence TACCGCTCCGCCGTCGACAATACCACT, what are the corresponding mRNA codons, tRNA anticodons, and amino acid (AA) sequence?
mRNA (5'→3') is $AUG\ GCG\ AGG\ CGG\ CAG\ CUG\ UUA\ UGG\ UGA$. The tRNA anticodons are $UAC\ CGC\ UCC\ GCC\ GUC\ GAC\ AAU\ ACC$ (no tRNA for the stop codon $UGA$). The amino acid sequence is Met–Ala–Arg–Arg–Gln–Leu–Leu–Trp–Stop.
What you are being asked to do
You are converting a DNA sequence into three things in order: the mRNA produced by transcription, the tRNA anticodons that pair with that mRNA, and the amino acids made during translation.
Transcribe the DNA into mRNA
Because the DNA starts with $TAC$, it is typically the template strand, which transcribes to the start codon $AUG$.
- Split DNA into codons:
DNA: $TAC\ CGC\ TCC\ GCC\ GTC\ GAC\ AAT\ ACC\ ACT$
- Make the complementary mRNA using base-pair rules (DNA $T\to$ RNA $A$, DNA $A\to$ RNA $U$, $C\leftrightarrow G$):
mRNA: $AUG\ GCG\ AGG\ CGG\ CAG\ CUG\ UUA\ UGG\ UGA$
Find the tRNA anticodons
tRNA anticodons are complementary to the mRNA codons:
$$ \begin{array}{l} AUG\to UAC\\ GCG\to CGC\\ AGG\to UCC\\ CGG\to GCC\\ CAG\to GUC\\ CUG\to GAC\\ UUA\to AAU\\ UGG\to ACC\\ UGA\to \text{STOP (no tRNA)} \end{array} $$
So the anticodons are: $UAC\ CGC\ UCC\ GCC\ GUC\ GAC\ AAU\ ACC$.
Translate mRNA codons into amino acids
Use the genetic code:
- $AUG$ = Met (start)
- $GCG$ = Ala
- $AGG$ = Arg
- $CGG$ = Arg
- $CAG$ = Gln
- $CUG$ = Leu
- $UUA$ = Leu
- $UGG$ = Trp
- $UGA$ = Stop
Amino acids: Met–Ala–Arg–Arg–Gln–Leu–Leu–Trp–Stop.
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