Given the mRNA sequence AUG ACU AGC UGG GGG UAU UAC UUU UAG, fill in the missing DNA sequence, the tRNA anticodons, and the amino acid sequence.
One valid set of answers is: DNA coding strand (5'→3') = ATG ACT AGC TGG GGG TAT TAC TTT TAG; tRNA anticodons (3'→5') = UAC UGA UCG ACC CCC AUA AUG AAA (no tRNA for stop); amino acids = Met–Thr–Ser–Trp–Gly–Tyr–Tyr–Phe–Stop.
What you are being asked to complete
You are given the mRNA, so you can (1) translate it into amino acids by reading codons (3 bases at a time), (2) write the matching tRNA anticodons by base pairing, and (3) write a matching DNA sequence by replacing $U$ with $T$ (coding strand) or by taking the complement (template strand).
Split the mRNA into codons
mRNA (5'→3'):
AUG | ACU | AGC | UGG | GGG | UAU | UAC | UUU | UAG
Translate codons to amino acids
Using the genetic code:
- $AUG$ = Met (start)
- $ACU$ = Thr
- $AGC$ = Ser
- $UGG$ = Trp
- $GGG$ = Gly
- $UAU$ = Tyr
- $UAC$ = Tyr
- $UUU$ = Phe
- $UAG$ = Stop
So the amino acid sequence is: Met–Thr–Ser–Trp–Gly–Tyr–Tyr–Phe–Stop
Find the tRNA anticodons
tRNA anticodons base-pair with mRNA codons ($A$ with $U$, $C$ with $G$) and are often written 3'→5':
- $AUG$ → $UAC$
- $ACU$ → $UGA$
- $AGC$ → $UCG$
- $UGG$ → $ACC$
- $GGG$ → $CCC$
- $UAU$ → $AUA$
- $UAC$ → $AUG$
- $UUU$ → $AAA$
- $UAG$ → no tRNA anticodon (stop codon is recognized by a release factor)
Write one correct DNA sequence
If you want the DNA coding (sense) strand, it matches the mRNA except $T$ replaces $U$:
DNA coding (5'→3'): ATG ACT AGC TGG GGG TAT TAC TTT TAG
(For reference, the DNA template (antisense) strand that is read by RNA polymerase would be complementary: 3'→5' TAC TGA TCG ACC CCC ATA ATG AAA ATC.)
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