An electric clothes dryer is connected to a 230.0 V source. What current does it draw if its resistance is 9.2 Ω?
Use Ohm’s law, $I = \frac{V}{R}$. With $V = 230.0\,\text{V}$ and $R = 9.2\,\Omega$, the current is $I = \frac{230.0}{9.2} = 25.0\,\text{A}$.
What you are being asked to find
You are given the voltage applied to the dryer and its electrical resistance. From those two values, you can find the current using Ohm’s law.
Apply Ohm’s law
Ohm’s law relates voltage $V$, current $I$, and resistance $R$: $$ I = \frac{V}{R} $$ Substitute the values: $$ I = \frac{230.0\,\text{V}}{9.2\,\Omega} = 25.0\,\text{A} $$
Quick reasonableness check
A resistance around $10\,\Omega$ at about $230\,\text{V}$ should give a current in the tens of amps, so $25\,\text{A}$ makes sense.
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