What is the displacement from position 1 (+45 cm) to position 2 (+33 cm)?
Displacement is final position minus initial position: $\Delta x = x_2 - x_1 = (+33\,\text{cm}) - (+45\,\text{cm}) = -12\,\text{cm}$. The negative sign means the motion is 12 cm in the negative direction.
What the question is asking
You are given an initial position and a final position on a 1D line. Displacement tells how much the position changes, including direction.
Use the displacement definition
Displacement is $$ \Delta x = x_f - x_i $$ Here, $x_i = +45\,\text{cm}$ and $x_f = +33\,\text{cm}$.
Substitute and compute
$$ \Delta x = (+33) - (+45) = -12\,\text{cm} $$
Interpret the sign
A displacement of $-12\,\text{cm}$ means the object ends 12 cm to the left (in the negative direction) of where it started.
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