A human heart pumps 60 mL of blood into the aorta in a 0.1 s stroke, accelerating blood from rest to 50 cm/s. What is the average acceleration of the blood?
The average acceleration is the change in velocity divided by the time: $a_{avg}=\Delta v/\Delta t$. Converting $50\,\text{cm/s}=0.50\,\text{m/s}$ and using $\Delta t=0.1\,\text{s}$, $$a_{avg}=\frac{0.50-0}{0.1}=5\,\text{m/s}^2.$$
What the problem is asking
You are given how fast the blood ends up moving and how long the heart takes to do that in one stroke. Average acceleration depends only on the velocity change and the time interval, not on the volume pumped.
Convert the final speed to SI units
Physics acceleration is usually reported in $\text{m/s}^2$, so convert:
$$50\,\text{cm/s}=\frac{50}{100}\,\text{m/s}=0.50\,\text{m/s}$$
Use the average-acceleration formula
Starting from rest means $v_i=0$. With $v_f=0.50\,\text{m/s}$ and $\Delta t=0.1\,\text{s}$:
$$a_{avg}=\frac{\Delta v}{\Delta t}=\frac{v_f-v_i}{\Delta t}=\frac{0.50-0}{0.1}=5\,\text{m/s}^2$$
Quick reasonableness check
A $0.50\,\text{m/s}$ speed increase in just $0.1\,\text{s}$ is a fairly quick ramp-up, so an acceleration of a few $\text{m/s}^2$ makes sense; here it is $5\,\text{m/s}^2$.
- Acceleration when stopping from 83 km/h in 4.0 s
- Speed of an Object Dropped from 10 m (Free Fall)
- Electric Field on the Axis of a Charged Ring
- Change in Temperature of Heated Copper Pipe
- Angle of Refraction as the Dependent Variable
- Particles in Solids vs Gases Table Answers
- Temperature Change of a Heated Copper Pipe
- Forca centripetale e automobilit (m=800 kg)
Comments (0)
Please to leave a comment.