Using the table of energy stored in 100 g of foods (apple 200 J, banana 340 J, chips 1 kJ, cooked beef 1 kJ, chocolate 1.5 kJ), what total energy is consumed by eating 50 g of chocolate and 200 g of banana?
Table: Food | Energy
Apple | 200 J
Banana | 340 J
Chips | 1 kJ
Cooked beef | 1 kJ
Chocolate | 1.5 kJ
50 g of chocolate provides $0.75\,\text{kJ}$ (750 J) and 200 g of banana provides $680\,\text{J}$ (0.68 kJ). Adding them gives a total energy of $0.75\,\text{kJ} + 0.68\,\text{kJ} = 1.43\,\text{kJ}$, which is $1430\,\text{J}$.
What you do with a “per 100 g” energy table
The table values are for 100 g servings, so you scale each food’s energy in proportion to the mass you actually eat, then add the energies.
Energy from 50 g of chocolate
Chocolate has $1.5\,\text{kJ}$ per $100\,\text{g}$.
50 g is half of 100 g, so: $$E_{\text{choc}} = \frac{50}{100}\times 1.5\,\text{kJ} = 0.5\times 1.5\,\text{kJ} = 0.75\,\text{kJ}$$ (That is $0.75\,\text{kJ} = 750\,\text{J}$.)
Energy from 200 g of banana
Banana has $340\,\text{J}$ per $100\,\text{g}$.
200 g is double 100 g, so: $$E_{\text{banana}} = \frac{200}{100}\times 340\,\text{J} = 2\times 340\,\text{J} = 680\,\text{J}$$ (That is $680\,\text{J} = 0.68\,\text{kJ}$.)
Add them in the same unit
Convert to the same unit and add: $$E_{\text{total}} = 0.75\,\text{kJ} + 0.68\,\text{kJ} = 1.43\,\text{kJ} = 1430\,\text{J}$$
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