A 12-sided solid has faces numbered 1 through 12. What is the probability of rolling a number greater than 5?

What the question is asking

You have a fair 12-sided solid labeled $1$ to $12$. To find the probability of getting a number greater than $5$, count how many faces meet the condition, then divide by the total number of faces.

Counting outcomes greater than 5

Numbers greater than $5$ are:

$6, 7, 8, 9, 10, 11, 12$

That is $7$ favorable outcomes.

Forming the probability

Total possible outcomes: $12$.

So the probability is

$$\frac{\text{favorable}}{\text{total}} = \frac{7}{12}.$$

Quick reasonableness check

More than half the numbers from $1$ to $12$ are greater than $5$, so the answer should be a bit more than $\tfrac{1}{2}$. Since $\tfrac{7}{12} \approx 0.583$, it makes sense.