AI-Verified Solution 8 views

Evaluate $h(-1)$ for the function $h(x)=-5x^3+4x-3x+2$.

Answer

First simplify the function: $h(x)=-5x^3+(4x-3x)+2=-5x^3+x+2$. Then substitute $x=-1$: $h(-1)=-5(-1)^3+(-1)+2=5-1+2=6$. So, $h(-1)=6$.

Explanation

What you are being asked to do

You are evaluating a function at a specific input. That means you replace every $x$ in the formula for $h(x)$ with $-1$, then simplify.

Simplify the expression inside the function

Combine like terms:

$$ -5x^3+4x-3x+2=-5x^3+(4x-3x)+2=-5x^3+x+2 $$

So the function is:

$$ h(x)=-5x^3+x+2 $$

Substitute $x=-1$ and compute

Now plug in $-1$ wherever you see $x$:

$$ \begin{aligned} h(-1) &= -5(-1)^3 + (-1) + 2 \\ &= -5(-1) - 1 + 2 \\ &= 5 - 1 + 2 \\ &= 6 \end{aligned} $$

Quick check

The key sign is $(-1)^3=-1$, so $-5(-1)$ becomes $+5$, which makes the final value positive.

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Skills You Achive
function evaluation substitution polynomial simplification integer arithmetic

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