Evaluate $h(-1)$ for the function $h(x)=-5x^3+4x-3x+2$.
First simplify the function: $h(x)=-5x^3+(4x-3x)+2=-5x^3+x+2$. Then substitute $x=-1$: $h(-1)=-5(-1)^3+(-1)+2=5-1+2=6$. So, $h(-1)=6$.
What you are being asked to do
You are evaluating a function at a specific input. That means you replace every $x$ in the formula for $h(x)$ with $-1$, then simplify.
Simplify the expression inside the function
Combine like terms:
$$ -5x^3+4x-3x+2=-5x^3+(4x-3x)+2=-5x^3+x+2 $$
So the function is:
$$ h(x)=-5x^3+x+2 $$
Substitute $x=-1$ and compute
Now plug in $-1$ wherever you see $x$:
$$ \begin{aligned} h(-1) &= -5(-1)^3 + (-1) + 2 \\ &= -5(-1) - 1 + 2 \\ &= 5 - 1 + 2 \\ &= 6 \end{aligned} $$
Quick check
The key sign is $(-1)^3=-1$, so $-5(-1)$ becomes $+5$, which makes the final value positive.
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