What are the products of the reaction FeBr2(aq) + K2CO3(aq)? A) FeO3 + KCBr B) FeK + BrCO3 C) FeCO3 + KBr D) FeC + KBrO3

What you are looking for in this reaction

Both reactants are aqueous ionic compounds, so this is set up like a double-displacement (ion swap) reaction. You swap the positive ions (cations) while keeping the negative ions (anions) together.

Identify the ions in each compound

• $FeBr_2(aq) \rightarrow Fe^{2+} + 2Br^-$
• $K_2CO_3(aq) \rightarrow 2K^+ + CO_3^{2-}$

Swap partners to form new compounds

• $Fe^{2+}$ combines with $CO_3^{2-}$ to make $FeCO_3$
• $K^+$ combines with $Br^-$ to make $KBr$

So the unbalanced products are $FeCO_3 + KBr$, which matches option C.

Balance the equation

To balance bromine and potassium, you need 2 potassium bromides:

$$FeBr_2(aq) + K_2CO_3(aq) \rightarrow FeCO_3(s) + 2KBr(aq)$$

(Also, $FeCO_3$ is insoluble, so it forms a precipitate, written as $(s)$.)