Pick the value you know
Choose pH, pOH, [H+] or [OH-] — whichever one the question gives you. The formula for that route is shown next to the selector so you can see which conversion is about to run.
Calcola il pH e il pOH delle tue soluzioni. Strumento di chimica essenziale per analisi di acidi e basi. Ottieni risultati precisi gratis online.
Enter one known acid-base value and the calculator returns pH, pOH, [H+], [OH-] and the classification, with the formula and the working. The arithmetic runs in your browser — no AI model decides the number.
Starting from with
Decimals, scientific notation and the textbook form all work: 0.001,
1e-3 or 10^-3.
Assumes 25 °C, where pH + pOH = 14.
Written out so you can hand in the working, not just the number. Check each line against your own arithmetic before you copy it.
Find pH, pOH, [H+] and [OH-] for chemistry homework and lab problems. Pick the value you already know, type it in — 1e-3 and 10^-3 both work — and press Calculate pH. You get all four values, an acidic / neutral / basic classification, and the formula with each step of the working. Everything runs in your browser at 25 °C, where pH + pOH = 14. No account, no upload, nothing saved.
Choose pH, pOH, [H+] or [OH-] — whichever one the question gives you. The formula for that route is shown next to the selector so you can see which conversion is about to run.
Decimals, scientific notation such as 1e-3, and the textbook form 10^-3 are all accepted. Concentrations take M or mol/L, which are the same unit. Nothing is sent anywhere — the logarithms run in your browser.
You get pH, pOH, [H+], [OH-] and the acidic, neutral or basic classification, plus the formula, the substitution and the answer written out line by line so you can hand in the working.
pH, pOH, [H+] and [OH-] are four ways of describing the same solution. Fix one and the other three follow, which is what makes this a conversion problem rather than a measurement.
Both are negative base-10 logarithms, so they compress a range spanning fourteen powers of ten into readable single-digit numbers. At 25 °C they always add to 14, which is why subtraction converts between them.
The actual concentrations, in moles per litre. They are recovered from a p-value by raising ten to its negative power, and their product is fixed at 1.0 × 10^-14 at 25 °C.
Acidic below pH 7, basic above it, neutral when [H+] equals [OH-]. This is a consequence of the numbers rather than a separate measurement, so the calculator derives it instead of asking for it.
The formulas are short. Almost every lost mark in this topic comes from notation or from the direction of the conversion, not from the chemistry.
The minus sign in pH = -log10([H+]) is doing real work: without it every acidic solution reports a negative pH. The other classic is entering 10^-3 as -3, or dropping the exponent entirely and typing 1.
Subtracting from 14 converts pH to pOH and back, but it does not convert a p-value into a concentration — that step needs a power of ten. Mixing the two produces answers that look plausible and are off by orders of magnitude.
Every example below is computed by the same code the calculator runs, so the numbers and the working match exactly what you get when you type your own value in.
If [H+] = 1 × 10^-3 M, then pH = 3. The concentration goes straight into the logarithm, and pOH follows by subtraction.
Full readout: pH 3.00, pOH 11.00, [H+] = 1.0 × 10^-3 M, [OH-] = 1.0 × 10^-11 M — acidic.
If pH = 4.5 at 25 °C, then pOH = 14 - 4.5 = 9.5. No logarithm is needed for the conversion itself, only for the concentrations that follow.
Full readout: pH 4.50, pOH 9.50, [H+] = 3.2 × 10^-5 M, [OH-] = 3.2 × 10^-10 M — acidic.
If pH = 2, then [H+] = 10^-2 = 0.01 M. Raising ten to the negative pH reverses the logarithm that produced it.
Full readout: pH 2.00, pOH 12.00, [H+] = 1.0 × 10^-2 M, [OH-] = 1.0 × 10^-12 M — acidic.
If [OH-] = 1 × 10^-4 M, the logarithm gives pOH = 4 first, and pH = 14 - 4 = 10 makes the solution basic.
Full readout: pH 10.00, pOH 4.00, [H+] = 1.0 × 10^-10 M, [OH-] = 1.0 × 10^-4 M — basic.
If pOH = 3, then pH = 14 - 3 = 11. A low pOH means a high pH, which catches students out more often than any other step here.
Full readout: pH 11.00, pOH 3.00, [H+] = 1.0 × 10^-11 M, [OH-] = 1.0 × 10^-3 M — basic.
Pure water at 25 °C has [H+] = 1 × 10^-7 M, which gives pH 7.00 and pOH 7.00 with [H+] equal to [OH-] — the definition of neutral.
Full readout: pH 7.00, pOH 7.00, [H+] = 1.0 × 10^-7 M, [OH-] = 1.0 × 10^-7 M — neutral.
EduSolver's AI tutor reads the whole problem, handles weak acids, buffers and titrations, and explains each step — then turns it into flashcards for the test.