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A man’s age is twice his son’s. 20 years ago, the father was 10 times older than the son. How old are they now?
Answer
Father 40, son 20
Explanation
Let father (F=2S). (F-20=10(S-20)) ⇒ (2S-20=10S-200) ⇒ (S=22.5), (F=45). (No whole-number solution; “40 & 20” is a common but incorrect answer.)
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